so... i'm not entirely sure what you mean by "cat gene combination", but my autistic brain (which interprets everything literally) saw an interesting question and i feel an infodump coming on in 3... 2... 1...
in a nutshell:
if you have a
specific gene configuration in mind - for example,
[C] [NN] [SS] [BBFF4] [NNMS] [NN0C] [AA] [BB] (since that's the first example mentioned in
this excellent guide, which i'm referencing heavily to put this post together) - the odds of receiving a cat with that
exact genome string (assuming that all alleles are equally likely to appear and that allele order matters) are currently 1 in 4671406080, or
0.0000000214%
some disclaimers:
- i have no idea whether the first assumption mentioned above ("all alleles are equally likely to appear") is true or not... and if your question was simply "is the 10 allele for White Level rarer than any of the other alleles?" then my answer is simply "i don't know"! xD
- the second assumption ("allele order matters") is much stronger than it needs to be (unless, for example, you really care whether your trade wind not-cat is NS or SN). with the exception of Color Group and Growth Rate (and possibly Mystery Gene), allele order has no effect on cat appearance or breeding outcomes.
- it's currently 3 AM where i am, and i'm very very eepy
- it's also been over 10 years since i last took a probability class (dear goodness i'm old /lh) so corrections are very welcome and appreciated! ^^
- even if i miraculously got all these numbers correct on the first try, they will become outdated in the future, as more alleles (e.g. the mercat species, unnatural color groups via alchemy, etc.) are added to the game. (exciting!!)
the math n stuff:
|
C - Not-Cat | 1 | 11 = 1 |
N - North
S - South
O - Null | 2 | 32 = 9 |
S - Shorthair
L - Longhair | 2 | 22 = 4 |
O - Orange/Cream
B - Black/Grey | 2 | 22 = 4 |
F - Full
D - Dilute | 2 | 22 = 4 |
1, 2, 3, 4 | 1 | 41 = 4 |
Y - Patterned (Not Solid)
N - Not Patterned (Solid) | 2 | 22 = 4 |
T - Striped
M - Marbled
S - Spotted
P - Pointed | 2 | 42 = 16 |
Y - White Marks
N - No White Marks | 2 | 22 = 4 |
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 | 1 | 111 = 11 |
C - Classic
P - Piebald
L - Left
R - Right
I - Inverse | 1 | 51 = 5 |
A - Fastest
B - Moderate
C - Slowest | 2 | 32 = 9 |
B - ???
L - ???
R - ???
Y - ??? | 2 | 42 = 16 |
now we multiply all the individual numbers of permutations (in the rightmost column of the table) together to get the number of permutations of the entire genome string:
1 * 9 * 4 * 4 * 4 * 4 * 4 * 16 * 4 * 11 * 5 * 9 * 16 =
4671406080
and then do a bit more wrangling to get that number into the form of a percent chance:
(1 / 4671406080) * 100 ≈ 2.1406831 * 10
-8 ≈
0.0000000214
and there ya go!
i'd say that's
quite a bit rarer than an albino